# Homework 13 Number 6

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84-g ice cube at 0°C is placed in 883 g of water at 24°C. What is the final temperature of the mixture?

I know that i can find Q using a given value for latent heat. and i know that Q=mc(delta)T. But I'm not sure how to put the equations together.

If (2) is true, then we can work out the problem in the following process -- first assume all ice melted in to zero degree water and find the heat needed. Then this heat would come from cooling the warm water down certain degrees. Find that temperature. Second, find the final temperature by mixing the cooled warm water and the zero-degree-ice-water. In all processes, heat flow would be in identical quantities for both warm and cold objects -- build your equation around this heat flow and we can solve the problem. For example, the last step would use $$M_{warm}c(T_w-T_f)=M_{ice}c(T_f-0)$$
Here $T_w$ is the temperature of the warm water and $T_f$ is the temperature of the final state of the mixed water. c is the specific heat of water.