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How much energy must be removed to change 3.5 kg of gold with initial temp of 2500 C to a temp of 660 C?

0 votes
605 views
Gold specific heat is 130J/kgxC
asked Mar 15, 2014 in Highschool Physics by Jinyi (120 points)
edited Mar 15, 2014 by Jinyi

1 Answer

0 votes

I think you just need to use the formula

Q=mcΔT

Where m is the mass of gold

c is the specific heat of gold

and ΔT is Tf -T(Note that T is usually in Kelvin, but the specific heat you gave was in terms of Celsius, so I think you can plug in the Celsius temperatures)

Q=3.5*130*(660-2500)

Q=-837200 J

Q=-837.2 kJ

Note this answer is negative because energy must be removed from the system to cool it down.

Hope that helps!

answered Mar 16, 2014 by Biomed94 (1,080 points)
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