# A basketball player achieves a hang time of 0.99 s

466 views
A basketball player achieves a hang time of
0.99 s in dunking the ball.
What vertical height will he attain? The
acceleration of gravity is 9.8 m/s^2
.
For the period of the hang time, the player traveled up and down so the vertical displacement is zero. Therefore, we have $\Delta y=0=V_y\Delta t-\frac 12 g\Delta t^2$. Here $\Delta t=0.99 s$. The goal is to find the initial vertical velocity $V_y$.
The maximum height is attained at half the hang time, which can then be calculated with $h=V_y(0.495)-\frac 12 g(0.495)^2$.