# A person can jump a maximum horizontal distance (by using a 45 degrees projectile angle) of 3 m on Earth.

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A person can jump a maximum horizontal distance (by using a 45 degrees projectile angle) of 3 m on Earth.

The acceleration of gravity is 9.8 m/s^What would be his maximum range on the

Moon, where the free-fall acceleration is g/6 ? Answer in units of m

asked Sep 15, 2014

In this case, one need to find the person's initial jump velocity which won't change on moon. At 45 degree, both x and y component of the initial velocity is the same and define the x and y component as v.

On the earth:

x-motion: $3=vt$

y-motion: $0=vt-\frac 12gt^2$

Solve for v.

Then on the moon:

x-motion: $x=vt$

y-motion: $0=vt-\frac 12 \frac g6 t^2$

Here, x and t are unknown. v is known from previous part. Solve for x.
answered Sep 15, 2014 by (21,750 points)