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1251 Prelab #9 Part 3

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For part 3, the field is nonuniform right? And I understand that there will be both a net force and a net torque, but I am just confused as to how to select the direction? I thought that the net force would vary depending on the direction of the e-field at any given point so would that be "other"? and for the torque I thought it would be the same, but that is not the right answer? Could someone help explain how to find the right answer?
asked Oct 19, 2014 in General by anonymous

1 Answer

0 votes
See where the field lines are dense, the field strength is higher. So the positive charge would experience a larger force compared to the negative charge.  Assume the field is symmetric about the x-axis, then the torque would be zero.
answered Oct 19, 2014 by PhysicsDude (21,750 points)
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